Four resistances $10$ $\Omega$, $5$ $\Omega$, $7$ $\Omega$ and $3$ $\Omega$ are connected so that they form the sides of a rectangle $AB$, $BC$, $CD$ and $DA$ respectively. Another resistance of $10$ $\Omega$ is connected across the diagonal $AC$. The equivalent resistance between $A$ and $B $ is .............. $\Omega$
Medium
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The figure can be drawn as follows
$ \Rightarrow $ ${R_{AB}} = 5\,\Omega $.
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