Four rods of same material and having the same cross section and length have been joined, as shown. The temperature of junction of four rods will be........ $^oC$
Medium
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$\frac{{{\rm{KA}}(90 - \theta )}}{l} = \frac{{{\rm{KA}}(\theta - 30)}}{l} + \frac{{{\rm{KA}}(\theta - {\rm{0}})}}{l} + \frac{{{\rm{KA}}(\theta - 60)}}{l}$
$90-\theta=3 \theta-90^{\circ}$
$\theta=45^{\circ}$ $C$
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