$\frac{\mathrm{Q}_{\mathrm{A}}}{\mathrm{Q}_{\mathrm{B}}}=\frac{1}{2}$
$\mathrm{Q}_{\mathrm{A}}=\frac{20}{3} \sigma \pi \mathrm{R}^{2}$ and $\mathrm{Q}_{\mathrm{B}}=\frac{40}{3} \sigma \pi \mathrm{R}^{2}$
$\sigma_{\mathrm{A}}=\frac{\mathrm{Q}_{\mathrm{A}}}{\text { area }}=\frac{20}{3} \frac{\sigma \pi \mathrm{R}^{2}}{4 \pi \mathrm{R}^{2}}=\frac{5 \sigma}{3}$
$\sigma_{\mathrm{B}}=\frac{40 \sigma \pi R^{2}}{4 \pi(2 R)^{2}}=\frac{5 \sigma}{6}$



Statement$ -1$ : When a charge $q$ is take from the centre of the surface of the sphere its potential energy changes by $\frac{{q\rho }}{{3{\varepsilon _0}}}$
Statement$ -2$ : The electric field at a distance $r(r < R)$ from centre of the sphere is $\frac{{\rho r}}{{3{\varepsilon _0}}}$