Four wires $AB,\,\,BC,\,\,CD,\,\,DA$ of resistance $4\, \Omega$ each and a fifth wire $BD$ of resistance $8\, \Omega$ are joined to form a rectangle $ABCD$ of which $BD$ is a diagonal. The effective resistance between the points $A$ and $B$ is
A$24\, ohm$
B$16\, ohm$
C$\frac{4}{3}\,ohm$
D$\frac{8}{3}\,ohm$
Medium
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D$\frac{8}{3}\,ohm$
d (d) Effective resistance between the points $A$ and $B$ is $R = \frac{{32}}{{12}} = \frac{8}{3}\,\Omega $
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