Question
$\frac{\sin 75^{\circ}}{\cos 15^{\circ}}=?$
✓
Answer
$\frac{\sin 75^{\circ}}{\cos 15^{\circ}}=\frac{\sin \left(90^{\circ}-15^{\circ}\right)}{\cos 15^{\circ}}$
$=\frac{\cos 15^{\circ}}{\cos 15^{\circ}} \quad \ldots .\left[\because \sin \left(90^{\circ}-\theta\right)=\cos \theta\right]$
$=1$
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