Question
In fig. TP =10 cm PS=6 cm
✓
Answer
Draw $R E \perp T S, T-E-S$
$\triangle R T P$ and $\triangle R P S$ have same height RE.
$\frac{A(\triangle R T P)}{A(\triangle R P S)}=\frac{T P}{P S} \quad \ldots . . .[\text { Triangles having equal height }]$
$\frac{A(\triangle R T P)}{A(\triangle R P S)}=\frac{10}{6} \quad \ldots ..[\text { Given }]$
$\therefore \frac{A(\triangle R T P)}{A(\triangle R P S)}=\frac{5}{3}$
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