Question
From given figure, In ∆ ABC, AB⊥ BC, AB =BC then $m \angle A =$ ?


$\therefore \angle A=\angle C \quad \ldots . . .[\text { Isosceles triangle theorem }]$
$\text { Let } \angle A=\angle C=x$
$\text { In } \triangle A B C$
$\angle A+\angle B+\angle C=180^{\circ}\ldots\left[\text { Sum of the measures of the angles of a triangle is } 180^{\circ}\right]$
$\therefore x+90^{\circ}+x=180^{\circ}$
$\therefore 2 x=90^{\circ}$
$\therefore x=\frac{90^{\circ}}{2}$
$\therefore x=45^{\circ}$
$\therefore m \angle A=45^{\circ}$
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