Question
From the following figure,
prove that $: AD=CE$.
prove that $: AD=CE$.
✓
Answer
In $\triangle ACD$ and $\triangle CBE,$
$DC= CB .......[$Given$]$
$AC = BE .......[$Given$]$
$\angle ACD = \angle CBE .......[$Proved Earlier$]$
$\therefore \triangle ACD ≅ \triangle CBE .......[SAS$ Criterion$]$
$\Rightarrow AD= CE ......[ \text{c.p.c.t.} ]$
$DC= CB .......[$Given$]$
$AC = BE .......[$Given$]$
$\angle ACD = \angle CBE .......[$Proved Earlier$]$
$\therefore \triangle ACD ≅ \triangle CBE .......[SAS$ Criterion$]$
$\Rightarrow AD= CE ......[ \text{c.p.c.t.} ]$
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