MCQ
General formula for carbohydrates is
- A${C_n}{H_{2n}}{O_{2n + 2}}$
- B${C_x}{({H_2}O)_{2x}}$
- ✓${C_x}{({H_2}O)_y}$
- DNone of these
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(Given data : Molar mass and the molal freezing point depression constant of benzene are $78 g mol ^{-1}$ and $5.12 K kg mol ^{-1}$, respectively)
$(I)\, (CH_3)_2P(CF_3)_3$ is non-polar and $(CH_3)_3P(CF_3)_2$ is polar molecule
$(II)\, CH_3 \widehat{P} CH_3$ bond angles are equal in $(CH_3)_3P(CF_3)_2$ molecule
$(III)\,PF_3$ will be more soluble in polar solvent than $SiF_4$
| $S \,No.$ | Time $(s)$ | Total pressure $(atm)$ |
| $1$ | $0$ | $0.5$ |
| $2$ | $100$ | $0.6$ |
Calculate the rate constant