Question
Given Arithmetic Progression $12, 16, 20, 24, . . .$ Find the $24th$ term of this progression.
✓
Answer
Given A.P. is $12,16,20,24, \ldots$
Where first term $a =12$
Second term $t_1=16$
Third term $t _2=20$
Common Difference $d=t_2-t_1=20-16=4$
We know that, $n^{\text {th }}$ term of an A.P. is
$t_n=a+(n-1) d$
We need to find the $24^{\text {th }}$ term,
Here $n=24$
Thus, $t _{24}=12+(24-1) \times 4$
$t_{24}=12+(23) \times 4=12+92=104$
Thus, $t _{24}=104$
Where first term $a =12$
Second term $t_1=16$
Third term $t _2=20$
Common Difference $d=t_2-t_1=20-16=4$
We know that, $n^{\text {th }}$ term of an A.P. is
$t_n=a+(n-1) d$
We need to find the $24^{\text {th }}$ term,
Here $n=24$
Thus, $t _{24}=12+(24-1) \times 4$
$t_{24}=12+(23) \times 4=12+92=104$
Thus, $t _{24}=104$
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