Given below are two statement :
Statement $I :$ If the number of turns in the coil of a moving coil galvanometer is doubled then the current sensitivity becomes double.
Statement $II :$ Increasing current sensitivity of a moving coil galvanometer by only increasing the number of turns in the coil will also increase its voltage sensitivity in the same ratio:
In the light of the above statement, choose the correct answer from the options given below :
JEE MAIN 2023, Medium
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For a moving coil galvanometer
$\text { BiNA }= k \theta$
$\theta=\left(\frac{ BNA }{ k }\right) i ; \text { Current sensitive }=\frac{ BNA }{ k }$
So, if $N$ is doubled then current sensitivity is doubled.
Voltage sensitivity
$B \frac{ V }{ R } NA = k \theta$
$V =\frac{ BNA }{ Rk } \theta, \text { as } N \text { is doubled } R \text { is also doubled. }$
So, no change in voltage sensitivity.
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