Question
Graphical method can be used only when the decision variables is:
✓
Answer
- Two
Graphical method can be used only when the decision variables is two.
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The order of the differential equation
$2\text{x}^2\frac{\text{d}^2\text{y}}{\text{dx}^2}-3\frac{\text{dy}}{\text{dx}}+\text{y}=0 \ \text{is}$
→$2\text{x}^2\frac{\text{d}^2\text{y}}{\text{dx}^2}-3\frac{\text{dy}}{\text{dx}}+\text{y}=0 \ \text{is}$
- 2
- 1
- 0
- not defined.
Choose the correct answer
If $\theta$ is the angle between two vectors $\vec{\text{a}}\ \text{and}\ \vec{\text{b}},\ \text{then}\ \vec{\text{a}}\cdot\vec{\text{b}}\geq0$ only when,
→If $\theta$ is the angle between two vectors $\vec{\text{a}}\ \text{and}\ \vec{\text{b}},\ \text{then}\ \vec{\text{a}}\cdot\vec{\text{b}}\geq0$ only when,
- $0<\theta<\frac{\pi}{2}$
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- $0<\theta<\pi$
- $0\leq\theta\leq\pi$
The value of $\sin \cot ^{-1} x$ :
→If $f(x) = |x^2 - 9x + 20|,$ then $f(x)$ is equal to :
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→The degree of the differntial equation $\left\{5+\Big(\frac{\text{dy}}{\text{dx}}\Big)^{2}\right\}^{\frac{5}{3}}=\text{x}^{5}\Big(\frac{\text{d}^{2}\text{y}}{\text{dx}^{2}}\Big)$ is:
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4
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2
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5
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10
In the interval (1, 2), function f(x) = 2|x - 1| + 3|x - 2| is:
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Choose the correct answer from the given four options. The feasible solution for a LPP is shown in. Let Z = 3x - 4y be the objective function.
Maximum of Z occurs at:
Maximum of Z occurs at:
The points of discontinuity of the function $\text{f(x)}=\begin{cases}\frac{1}{5}(2\text{x}^2+3),&\text{x}\leq1\\6-5\text{x},&1<\text{x}<3\\\text{x}-3,&\text{x}\geq3\end{cases}$ is (are):
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If f(x) = |x - 3| and g(x) = fof(x), then for x > 10, g'(x) is equal to:
- 1
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