c
(c)Time taken by water to reach the bottom = \(t = \sqrt {\frac{{2(H - D)}}{g}} \) and velocity of water coming out of hole, \(v = \sqrt {2gD} \) Horizontal distance covered \(x = v \times t\) = \(\sqrt {2gD} \times \sqrt {\frac{{2(H - D)}}{g}} \)= \(2\sqrt {D(H - D)} \)