Question
$\text{H}_2\text{O}_2$ is a better oxidizing agent than water. Explain.

Answer

$\text{H}_2\text{O}_2$ is a better oxidizing agent than water.
$\text{H}_2\text{O}_2$ acts as an oxidizing agent as well as in alkaline medium.
$\text{H}_2\text{O}_2+2\text{H}^++2\text{e}^-\xrightarrow{\ \ \text{Acid }\ }2\text{H}_2\text{O}\ \ \ \text{E}^\circ=1.77\text{V}$
$\text{H}_2\text{O}_2+\text{OH}^-+2\text{e}^-\xrightarrow{\ \ \text{Alkaline}\ \ }3\text{OH}^-\ \ \ \text{E}^\circ=0.88\text{V}$
Oxidation state of oxygen changes from -1 to -2.
Oxidising nature of $\text{H}_2\text{O}_2$ can be interpreted account of possession of labile oxygen.
$\text{H}_2\text{O}_2\xrightarrow{\ \ \ \ \ }\text{H}_2\text{O}\ \ +\ \ \text{H}_2\text{O}\ \ +\ \ \text{O}$
When water acts as an oxidizing ageng, it is reduced to $\text{H}_2$.
Water reacts with number of active metals whose electrode potential is less than -0.83V.
$2\text{Na}\ \ \ \ \ \ \ \ \ +\ \ \ \ \ \ \ 2\text{H}_2\text{O}\xrightarrow{\ \ \ \ \ \ \ \ }2\text{NaOH}\ \ \ \ \ \ \ +\ \ \ \ \ \ \ \ \ \text{H}_2\\\text{Reductant}\ \ \ \ \ \ \ \ \text{Oxidant}$

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