b
(b)Electronic configuration of \(_{16}{S^{32}} = 1{s^2},2{s^2},2{p^6},3{s^2},3{p^4}\). In the last orbit it has only \(6\) electron. So it require \(2\) electron to complete its octet, therefore it share \(2\) electron with two hydrogen atom and forms \(2\) covalent bond with it.