$\,\begin{array}{*{20}{c}}{\,\,}\\{\begin{array}{*{20}{c}}{\,\,\,\,\,O}&{}&{}&{\,\,\,\,\,\,\,\,\,O}&{}\end{array}}\\{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,||}&{}&{}&{\,\,\,\,\,\,\,\,\,\,\,\,|| \,}&{}\end{array}}\\{H - O - S - O - O - S - O - H}\\{\begin{array}{*{20}{c}}
\begin{array}{l}\,\,\,\,\,\,\,\,\,\,|| \\ \,\,\,\,\,\,\,\,\,O \end{array} & \begin{array}{l}\\ \end{array}&\begin{array}{l}\\ \end{array}&\begin{array}{l}\,\,\,\,\,|| \\ \,\,\,\,O\end{array}&\begin{array}{l}\\ \end{array}\end{array}}\end{array}$
અહીં જોડાયેલા ઓક્સિજન પરમાણુઓમાંના બે $'O\ '$ પેરોક્સાઇડ લીંકેજમાં હોવાથી તેમનો ઓ.આંક $-1$ થાય.
આથી, $\ce{H_2SO_4}$ માં $2(+1) + 2(X) + 2(-1) + 6(-2) = 0$
$\therefore X = + 6$