MCQ
Haemoglobin contains $0.33\%$ of iron by weight. The molecular weight of haemoglobin is approximately $67200$. The number of iron atoms (At. wt. of $Fe = 56$) present in one molecule of haemoglobin is
- A$6$
- B$1$
- ✓$4$
- D$2$
$\therefore $ $67200\,gm$ $Hb $ = $\frac{{67200 \times 0.33}}{{100}}\,gm\;Fe$
$gm$ atom of $Fe$ = $\frac{{672 \times 0.33}}{{56}} = 4$.
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Reason : Butter has an affinity towards benzene.
|
LIST $I$ (Precipitating reagent and conditions) |
LIST $II$ (Cation) |
| $A$ $\mathrm{NH}_4 \mathrm{Cl}+\mathrm{NH}_4 \mathrm{OH}$ | $I$ $\mathrm{Mn}^{2+}$ |
| $B$ $\mathrm{NH}_4 \mathrm{OH}+\mathrm{Na}_2 \mathrm{CO}_3$ | $II$ $\mathrm{Pb}^{2+}$ |
| $C$ $\mathrm{NH}_4 \mathrm{OH}+\mathrm{NH}_4 \mathrm{Cl}+\mathrm{H}_2 \mathrm{~S}$ gas | $III$ $\mathrm{Al}^{3+}$ |
| $D$ dilute $\mathrm{HCl}$ | $IV$ $\mathrm{Sr}^{2+}$ |
Choose the correct answer from the options given below: