.......... $\times 10^{13} \mathrm{~Hz}$ છે. (નજીકનો પૂર્ણાંક).
[આપેલ : $R_H$ (રીડબર્ગ અયળાંક) = $2.18 \times 10^{-18} \mathrm{~J}, h$ (પ્લાન્ક
અચળાંક) $=6.6 \times 10^{-34}$ $J.s.$]
\(\lambda=\frac{\mathrm{hv}}{\mathrm{mv}^2}\)
\(\frac{\mathrm{mv}^2}{\mathrm{~h}}=\frac{\mathrm{v}}{\lambda}=\mathrm{v} \text { (frequency) }\)
\(\text { Given } \frac{1}{2} \mathrm{mv}^2=2.18 \times 10^{-18} \mathrm{~J}\)
\(\mathrm{~h}=6.6 \times 10^{-34}\)
\(\mathrm{v}=\frac{4.36 \times 10^{-18}}{6.6 \times 10^{-34}}=660.60 \times 10^{13} \mathrm{~Hz}\)
\(\approx 661 \times 10^{13} \mathrm{~Hz}\)
$n$ | $l$ | $m_l$ | |
$A$ | $3$ | $3$ | $-3$ |
$B$ | $3$ | $2$ | $-2$ |
$C$ | $2$ | $1$ | $+1$ |
$D$ | $2$ | $2$ | $+2$ |
ઉપરોક્તમાંથી સાચા સેટની સંખ્યા......... છે
(આપેલું છે : ઈલેકટ્રોનનું દળ $=9.1 \times 10^{-31} \,kg$, પ્લાન્ક અચળાંક $h =6.63 \times 10^{-34}\, Js$ )