\(\lambda_{3}=\frac{2 \pi\left(4.65 \times 10^{-10}\right)}{3}\)
\(\lambda_{3}=9.7 \mathrm{A}\)
[Rhc=13.6 eV, $\mathrm{hc}=1242 \mathrm{eV} \mathrm{nm}, \mathrm{h}=6.6 \times 10^{-34} \mathrm{J-s}$ અને હાઈડ્રોજન પરમાણુનું દળ $\sim 1.6 \times 10^{-27} \mathrm{~kg}$ લો.]