$\begin{matrix}
CH-C{{O}_{2}}H \\
\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \\
CH-C{{O}_{2}}H \\
\end{matrix}\xrightarrow[(two\,mole)]{NaOH}(A)\xrightarrow{electrolysis}(B);$
${\left( {C{H_3}} \right)_3}C - CH = C{H_2}\xrightarrow[{\left( {ii} \right)\,NaB{H_4} + NaOH}]{{\left( i \right)\,Hg{{\left( {C{H_3}COO} \right)}_2};\,THF}}\,?$