MCQ
Hemoglobin contains $0.34 \%$ of iron by mass. The number of $Fe$ atoms in $3.3 g$ of hemoglobin is.(Given : Atomic mass of $Fe$ is $56\,u , N _{ A }$ in $6.022$ $\left.\times 10^{23} mol ^{-1}\right)$
  • A
    $1.21 \times 10^{5}$
  • B
    $12.0 \times 10^{16}$
  • $1.21 \times 10^{20}$
  • D
    $3.4 \times 10^{22}$

Answer

Correct option: C.
$1.21 \times 10^{20}$
c
No. of Fe atoms $=\frac{0.34}{100} \times \frac{3.3}{56} \times 6.022 \times 10^{23}$ $=1.206 \times 10^{20}$

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