The cobalt atom in \(Hg \left[ Co ( SCN )_{4}\right]\) carries +2 charge and has \(3 d ^{7}\) as the outer electronic configuration.
Here Hg shows +2 oxidation state and the compound is known as Mercuric tetrathiocyanatocobaltate(II).
It contains three unpaired electrons.
For three unpaired electrons, the expression becomes \(\mu_{e f f}=\sqrt{3(3+2)} B \cdot M .=\sqrt{15} B \cdot M\)
Therefore, option \(C\) is correct.
સૂચિ $-I$ | સૂચિ $-II$ |
$A$ $Ni ( CO )_{4}$ | $I$ $sp ^{3}$ |
$B$ ${\left[ Ni ( CN )_{4}\right]^{2-} }$ | $II$ $S p^{3} d^{2}$ |
$C$ ${\left[ Co ( CN )_{6}\right]^{3-} }$ | $III$ ${d^{2}}$ |
$D$ ${\left[ CoF _{6}\right]^{3-} }$ | $IV$ ${s p^{3}}{d s p^{2}}$ |
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