How many calories of heat will be produced approximately in a $210\, watt$ electric bulb in $5$ minutes .............. $cal $
Easy
Download our app for free and get startedPlay store
(d) $H = \frac{{{V^2}t}}{{R \times J}}\,Calories = \frac{{P\,t}}{J} = \frac{{210 \times 5 \times 60}}{{4.2}} = 15000\,cal$
art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    Which device can convert all electrical energy into heat
    View Solution
  • 2
    Assertion : Ohm's law is applicable for all conducting elements.

    Reason : Ohm's law is a fundamental law

    View Solution
  • 3
    In the circuit shown, the reading of the ammeter (ideal) is the same with both switches  open as with both closed find the value of resistance $R$ in $ohm$ . ................ $\Omega$
    View Solution
  • 4
    A galvanometer together with an unknown resistance in series is connected to two identical batteries each of $1.5\, V$. When the batteries are connected in series, the  galvanometer records a current of $1\,A$, and when batteries are in parallel the current is $0.6\,A$.  What is the internal resistance of the battery ?
    View Solution
  • 5
    If the length of potentiometer wire is increased, then the length of the previously obtained balance point will
    View Solution
  • 6
    In a building there are $15$ bulbs of $45\; \mathrm{W}, 15$ bulbs of $100\; \mathrm{W}, 15$ small fans of $10 \;\mathrm{W}$ and $2$ heaters of $1 \;\mathrm{kW}$. The voltage of electric main is $220\; \mathrm{V}$. The minimum fuse capacity (rated value) of the building will be: .......... $A$
    View Solution
  • 7
    In a potentiometer experiment, the galvanometer shows no deflection when a cell is connected across $60\, cm$ of the potentiometer wire. If the cell is shunted by a resistance of $6\,\Omega $, the balance is obtained across $50\, cm$ of the wire. The internal resistance of the cell is .............. $\Omega $
    View Solution
  • 8
    In order to increase the resistance of a given wire of uniform cross section to four times its value, a fraction of its length is stretched uniformly till the full length of the wire becomes $\frac{3}{2}$ times the original length what is the value of this fraction?
    View Solution
  • 9
    When a current $I$ is passed through a wire of constant resistance, it produces a potential difference $V$ across its ends. The graph drawn between $\log\, I$ and $\log\, V$ will be
    View Solution
  • 10
    A null point is found at $200\,cm$ in potentiometer when cell in secondary circuit is shunted by $5\,\Omega$. When a resistance of $15\,\Omega$ is used for shunting null point moves to $300\,cm$. The internal resistance of the cell is $..............\,\Omega$.
    View Solution