MCQ
How many moles of magnesium phosphate, $Mg_3(PO_4)_2$ will contain $0.25$ mole of oxygen atoms ?
- A$1.25 \times 10^{-2}$
- B$2.5 \times 10^{-2}$
- C$0.02$
- ✓$3.125 \times 10^{-2}$
✓
Answer
Correct option: D.
$3.125 \times 10^{-2}$
d
In one $\mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ molecule no of oxygen atoms $=8$
In one $\mathrm{Mg}_{3}\left(\mathrm{PO}_{4}\right)_{2}$ molecule no of oxygen atoms $=8$
So if there is $M\; mole$ of $Mg_3\left(\mathrm{PO}_{4}\right)_{2}$ molecules then no of moles of oxygen atoms is $=\mathrm{M} \times 8$
According to question,
$M \times 8=0.25$
$\Rightarrow M=0.03125=3.125 \times 10^{-2}$
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