MCQ
How much lime $(CaO)$ can be obtained by heating $200\, kg$ of limestone which is $95\%$ pure ? ............... $\mathrm{kg}$
  • $106.4$
  • B
    $53.2$
  • C
    $10.64$
  • D
    $5.32$

Answer

Correct option: A.
$106.4$
a
molecular mass of $CaCO _3=100$

molecular mass of $CaO=56$

$100 \mathrm{g}$ $CaCO_3$ make $56 \mathrm{g}$ $CaO$

$200000 \mathrm{g}$ will make $=56\times 200000 / 100$

$=112 \mathrm{kg}$

for $95 \%=106.40 \mathrm{kg}$ of $\mathrm{CaO}$

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