MCQ
How much volume of water is to be added to dilute $10\,ml$ of $10\,N\,HCl$ to make it decinormal? .............. $\mathrm{ml}$
- ✓$990$
- B$1010$
- C$100$
- D$1000$
✓
Answer
Correct option: A.
$990$
a
$\mathrm{M}_{\mathrm{eq}}$ of conc. $\mathrm{HCl}=\mathrm{M}_{\infty}$ of dil. $HCl$
$\mathrm{M}_{\mathrm{eq}}$ of conc. $\mathrm{HCl}=\mathrm{M}_{\infty}$ of dil. $HCl$
$10 \times 10=V \times \frac{1}{10}$
$V=1000\, \mathrm{ml}$
Thus, $990\, \mathrm{ml}$ of water should be added to $10 \,\mathrm{ml}$ of conc. $HCl$ to get decinormal solution.
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