MCQ
Hydroxide soluble in ammonia is
- A$Al{(OH)_3}$
- B$Fe{(OH)_3}$
- C$Cr{(OH)_3}$
- ✓$Cu{(OH)_2}$
✓
Answer
Correct option: D.
$Cu{(OH)_2}$
d
(d) Due to formation of complex
(d) Due to formation of complex
$Cu{(OH)_2} + 4N{H_3}\, \to \,[Cu{(N{H_3})_4}]{(OH)_2}$
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