Identify $B$ formed in the reaction.$\begin{array}{l} Cl -\left( CH _2\right)_4- Cl \xrightarrow{\text { excess } NH _3} A \xrightarrow{ NaOH } \\ B + H _2 O + NaCl\end{array}$
- A
- B$ \mathrm{H}_2 \mathrm{~N}-\left(\mathrm{CH}_2\right)_4-\mathrm{NH}_2 $
- C$ {\mathrm{Cl}} N^+ \mathrm{H}_3-\left(\mathrm{CH}_2\right)_4-\stackrel{+}{\mathrm{N}} \mathrm{H}_3 \mathrm{Cl}^{-}$
- D
JEE MAIN 2024, Difficult
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