MCQ
If $A = \{a, b, c, d\},$ then a relation $R = \{(a, b), (b, a), (a, a)\}$ on $A$ is:
  • Symmetric and transitive only.
  • B
    Reflexive and transitive only.
  • C
    Symmetric only.
  • D
    Transitive only.

Answer

Correct option: A.
Symmetric and transitive only.
Given that $A = \{a, b, c, d\}$
then $a$ relation $R = \{(a, b), (b, a), (a, a)\}$ on $A.$
$(a, b), (b, a) \in\text{R}$
$\Rightarrow R$ is symmetric.
Also for $(a, a) R$ is symmetric.

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Consider the function $f:(-\infty, \infty) \rightarrow(-\infty, \infty)$ defined by $f(x)=\frac{x^2-a x+1}{x^2+a x+1}, 0 < a < 2 .$

$1.$ Which of the following is true?

$(A)$ $(2+a)^2 f^{\prime \prime}(1)+(2-a)^2 f^{\prime \prime}(-1)=0$

$(B)$ $(2-a)^2 f^{\prime}(1)-(2+a)^2 f^{\prime \prime}(-1)=0$

$(C)$ $f^{\prime}(1) f^{\prime}(-1)=(2-a)^2$

$(D)$ $f^{\prime}(1) f^{\prime}(-1)=-(2+a)^2$

$2.$ Which of the following is true?

$(A)$ $f(x)$ is decreasing on $(-1,1)$ and has a local minimum at $x=1$

$(B)$ $f(x)$ is increasing on $(-1,1)$ and has a local maximum at $x=1$

$(C)$ $f(x)$ is increasing on $(-1,1)$ but has neither a local maximum nor a local minimum at $x=1$

$(D)$ $f(x)$ is decreasing on $(-1,1)$ but has neither a local maximum nor a local minimum at $x=1$

$3.$ Let $g(x)=\int_0^{e^x} \frac{f^{\prime}(t)}{1+t^2} d t$ which of the following is true?

$(A)$ $g^{\prime}(x)$ is positive on $(-\infty, 0)$ and negative on $(0, \infty)$

$(B)$ $g^{\prime}(x)$ is negative on $(-\infty, 0)$ and positive on $(0, \infty)$

$(C)$ $\mathrm{g}^{\prime}(\mathrm{x})$ changes sign on both $(-\infty, 0)$ and $(0, \infty)$

$(D)$ $g^{\prime}(x)$ does not change sign on $(-\infty, \infty)$

Give the answer question $1,2$ and $3.$

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