If a parallelopiped is formed by planes drawn through the points … - Vidyadip

MCQ

If a parallelopiped is formed by planes drawn through the points $(5, 8, 10)$ and $(3, 6, 8)$ parallel to the coordinate planes, then the length of diagonal of the parallelopiped is:

✓
$2\sqrt{3}$
B
$3\sqrt{2}$
C
$\sqrt{2}$
D
$\sqrt{3}$

✓

Answer

Correct option: A.

$2\sqrt{3}$

Given parallelepiped passes through $A(5, 8, 10)$ and $B(3, 6, 8)$
$\therefore$ Length of the diagonal,
$\text{AB}=\sqrt{(5-3)^2+(8-6)^2+(10-8)^2}$
$=\sqrt{4+4+4}$
$=2\sqrt{3}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "M.C.Q (1 Marks)" from Introduction to Three Dimensional Geometry→Introduction to Three Dimensional Geometry — all question types→Maths STD 11 Science question papers→CBSE Board STD 11 Science question papers→CBSE Board question paper generator→

Similar questions

If ${\left( {10} \right)^9} + 2{\left( {11} \right)^1}{\left( {10} \right)^8} + 3{\left( {11} \right)^2}{\left( {10} \right)^7} + ..\;.\;.\;.\; + 10\left( {{{11}^9}} \right) = \;k{\left( {10} \right)^9}$ ,then $k $ is equal to

If $A, B, C$ be the angles of a triangle, then $\sum {\frac{{\cot A + \cot B}}{{\tan A + \tan B}} = } $

For what value of $\theta, 1$ lies between the roots of the quadratic equation $3\text{x}^2 – 3\sin\theta \text{x} – 2\cos^2\theta = 0$

Let A and B be two sets in the same universal set. Then, A - B =

If $x = {\log _b}a,\,\,y = {\log _c}b,\,\,\,z = {\log _a}c$, then $xyz$ is

For the ellipse $\frac{{{x^2}}}{{64}} + \frac{{{y^2}}}{{28}} = 1$, the eccentricity is

${\left( {\frac{{1 + \cos \phi + i\sin \phi }}{{1 + \cos \phi - i\sin \phi }}} \right)^n} = $

If $-2<2\text{x}-1<2$ then the value of $x$ lies in the interval:

$x^r$ occurs in the expansion of ${\left( {{x^3} + \frac{1}{{{x^4}}}} \right)^n}$ provided -

In the expansion of ${\left( {\frac{{1 + x}}{{1 - x}}} \right)^2}$, the coefficient of ${x^n}$ will be