MCQ
If $a,\,b,\,c$ are in $A.P.$, then $(a + 2b - c)$ $(2b + c - a)$ $(c + a - b)$ equals
- A$\frac{1}{2}abc$
- B$abc$
- C$2\ abc$
- ✓$4\ abc$
$ = (a + a + c - c)(a + c + c - a)(2b - b)$ $ = 4\,abc.$
$(\because a,b,c$ are in $A.P.$,
$\therefore 2b = a + c)$.
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