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MODEL PAPER 1 — Physics STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 SciencePhysicsMODEL PAPER 11 Mark
Question
If an electron is accelerated by $8.8 \times 10^{14} m / s ^2$ , then electric field required for acceleration is $($given specific charge of the electron $=1.76 \times 10^{11} Ckg ^{-1} )Z$
✓

Answer

$(b) : 50 V \ cm ^{-1}$
Explanation: $a=8.8 \times 10^{14} m / s ^2$
$\frac{e}{m}=1.76 \times 10^{11} C^{-1} \ kg^{-1}$
$a=\frac{F}{m}=\frac{e E}{m}=\left(\frac{e}{m}\right) E$
$8.8 \times 10^{14}=1.76 \times 10^{11} \times E$
$E=\frac{8.8 \times 10^{14}}{1.76 \times 10^{11}}$
$=5000 \ Vm ^{-1}$
$=50 \ Vcm ^{-1}$

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