MCQ
If an interference pattern have maximum and minimum intensities in $36 : 1$ ratio then what will be the ratio of amplitudes
- A$5:7$
- B$7:4$
- C$4:7$
- ✓$7:5$
✓
Answer
Correct option: D.
$7:5$
d
(d)$\frac{{{I_{\max }}}}{{{I_{\min }}}} = {\left( {\frac{{\frac{{{a_1}}}{{{a_2}}} + 1}}{{\frac{{{a_1}}}{{{a_2}}} - 1}}} \right)^2} \Rightarrow \frac{{{a_1} + {a_2}}}{{{a_1} - {a_2}}} = 6$
$\frac{{{a_2}}}{{{a_1}}} = 7:5$
(d)$\frac{{{I_{\max }}}}{{{I_{\min }}}} = {\left( {\frac{{\frac{{{a_1}}}{{{a_2}}} + 1}}{{\frac{{{a_1}}}{{{a_2}}} - 1}}} \right)^2} \Rightarrow \frac{{{a_1} + {a_2}}}{{{a_1} - {a_2}}} = 6$
$\frac{{{a_2}}}{{{a_1}}} = 7:5$
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