MCQ
If an interference pattern have maximum and minimum intensities in $36: 1$ ratio then what will be the ratio of amplitudes
  • A
    $5: 7$
  • B
    $7: 4$
  • C
    $4: 7$
  • $7: 5$

Answer

Correct option: D.
$7: 5$
$\frac{I_{\max }}{I_{\min }}=\left(\frac{\frac{a_1}{a_2}+1}{\frac{a_1}{a_2}-1}\right)^2 $
$\Rightarrow \frac{a_1+a_2}{a_1-a_2}=6 $
$\frac{a_2}{a_1}=7: 5$

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