If at temperature ${T_1} = 1000K,$ the wavelength is $1.4 \times {10^{ - 6}}m,$ then at ....... $K$ temperature the wavelength will be $2.8 \times {10^{ - 6}}m$
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(a) ${\lambda _m} \propto \frac{1}{T}$==> $\lambda {m_1}{T_1} = \lambda {m_2}{T_2}$
==> ${T_2} = \frac{{\lambda {m_1}{T_1}}}{{\lambda {m_2}}} = \frac{{1.4 \times {{10}^{ - 6}} \times 1000}}{{2.8 \times {{10}^{ - 6}}}} = 500K$
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