MCQ
If $\cos \theta=\frac{1}{2}$, then $\cos \theta-\sec \theta$ is equal to
  • A
    $\frac{3}{2}$
  • $-\frac{3}{2}$
  • C
    $\frac{\sqrt{3}}{2}$
  • D
    $-\frac{\sqrt{3}}{2}$

Answer

Correct option: B.
$-\frac{3}{2}$
(B)$-\frac{3}{2}$
We have, $\cos \theta=\frac{1}{2}$. Therefore, $\sec \theta=\frac{1}{\cos \theta}=2$. Hence, $\cos \theta-\sec \theta=\frac{1}{2}-2=-\frac{3}{2}$
ALITER $\cos \theta=\frac{1}{2} \Rightarrow \theta=60^{\circ} \Rightarrow \sec \theta=\sec 60^{\circ}=2$
Hence, $\quad \cos \theta-\sec \theta=\frac{1}{2}-2=-\frac{3}{2}$

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