MCQ
If equilibrium constant of

$C{H_3}COOH + {H_2}O \rightleftharpoons C{H_3}CO{O^ - } + {H_3}{O^ + }$ is $1.8 \times 10^{-5}$, equilibrium constant for

$C{H_3}COOH + O{H^ - } \rightleftharpoons C{H_3}CO{O^ - } + {H_2}O$

  • A
    $1.8 \times {10^{ - 9}}$
  • $1.8 \times {10^{ 9}}$
  • C
    $5.55 \times {10^{ - 9}}$
  • D
    $5.55 \times {10^{ 10}}$

Answer

Correct option: B.
$1.8 \times {10^{ 9}}$
b
$\mathrm{K}^{1}=\frac{1}{\mathrm{K}_{\mathrm{h}}}=\frac{\mathrm{K}_{\mathrm{a}}}{\mathrm{K}_{\mathrm{w}}}=\frac{1.8 \times 10^{-5}}{10^{-14}}$

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