MCQ
If $\text{HCl}$ is added to pure water at $25^\circ C$ the ionic product of water will be :
  • A
    $ > 10^{-14} $
  • B
    $ < 10^{-14} $
  • $ 10^{-14} $
  • D
    $ > 10^{-10} $

Answer

Correct option: C.
$ 10^{-14} $
For ionic product of pure water :
$ {\left[\mathrm{H}^{+}\right]=10^{-7} \mathrm{M}} $
$ {\left[\mathrm{OH}^{-}\right]=10^{-7} \mathrm{M}} $
$\text { Product, } \mathrm{K}_{\mathrm{W}}=10^{-14}$
lonic Product $\text{Kw}$ of water is dependent only on temperature so it will remain same,
$ \mathrm{K}_{\mathrm{W}}=10^{-14}$.

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