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3 and 4 . determinant and metrices — Maths STD 12 Science — Question

Gujarat BoardEnglish MediumSTD 12 ScienceMaths3 and 4 . determinant and metrices1 Mark
MCQ
If $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right]$, then $(a,b,c,d) = $
  • A
    $(1,\,6,\,2,\,5)$
  • B
    $(1, 2, 7, 5)$
  • ✓
    $(1, 2, -7, 5)$
  • D
    $(-1, -2, 7, -5)$
✓

Answer

Correct option: C.
$(1, 2, -7, 5)$
c
(c) $\left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right]$

==> $\left[ {\begin{array}{*{20}{c}}a&c\\b&d\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}2&{ - 3}\\4&0\end{array}} \right] - \left[ {\begin{array}{*{20}{c}}1&4\\2&{ - 5}\end{array}} \right] = \left[ {\begin{array}{*{20}{c}}1&{ - 7}\\2&5\end{array}} \right]$

==> $(a,b,c,d) = (1,\,\,2,\,\, - 7,\,\,5)$.

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