If _ x 2 (x - 2)( x^2 + (a - 2)x - 2a) ( x^2 - 4x + 4) = 7,then '… - Vidyadip

MCQ

If $\mathop {\lim }\limits_{x \to 2} \frac{{\tan (x - 2)({x^2} + (a - 2)x - 2a)}}{{({x^2} - 4x + 4)}} = 7$,then $'a'$ is -

A
$3$
✓
$5$
C
$6$
D
$7$

✓

Answer

Correct option: B.

$5$

b
$\mathop {\lim }\limits_{x \to 2} \frac{{\tan (x - 2)({x^2} + (a - 2)x - 2a)}}{{{{(x - 2)}^2}}} = 7$

$\Rightarrow a+2=7 \Rightarrow a=5$

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