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Functions(p-1) — Maths (commerce) STD 11 Commerce / Arts — Question

Maharashtra BoardEnglish MediumSTD 11 Commerce / ArtsMaths (commerce)Functions(p-1)3 Marks
Question
If $\mathrm{f}(\mathrm{x})=\left\{\begin{array}{ll}x^2+3, & x \leq 2 \\ 5 x+7, & x>2\end{array}\right.$, then find
(i) $f(3)$
(ii) $f(2)$
(iii) $f(0)$
✓

Answer

$
\begin{aligned}
& f(x)=x^2+3, x \leq 2 \\
& =5 x+7, x>2
\end{aligned}
$
(i) $f(3)=5(3)+7=15+7=22$
(ii) $f(2)=2^2+3=4+3=7$
(iii) $f(0)=0^2+3=3$

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