If one end of a wire is fixed with a rigid support and the other end is stretched by a force of $10 \,N,$ then the increase in length is $0.5\, mm$. The ratio of the energy of the wire and the work done in displacing it through $1.5\, mm$ by the weight is
  • A$\frac{1}{3}$
  • B$\frac{1}{4}$
  • C$\frac{1}{2}$
  • D$1$
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