MCQ
If ratio of maximum and minimum intensities is $36 : 1$ in an interference pattern then, ratio of amplitudes of interfering waves is
- A$3 : 7$
- B$7 : 4$
- C$4 : 7$
- ✓$7 : 5$
✓
Answer
Correct option: D.
$7 : 5$
d
$\frac{\mathrm{I}_{\max }}{\mathrm{I}_{\min }}=\left(\frac{\mathrm{a}_{1}+\mathrm{a}_{2}}{\mathrm{a}_{1}-\mathrm{a}_{2}}\right)^{2}=\frac{36}{1}$
$\frac{\mathrm{I}_{\max }}{\mathrm{I}_{\min }}=\left(\frac{\mathrm{a}_{1}+\mathrm{a}_{2}}{\mathrm{a}_{1}-\mathrm{a}_{2}}\right)^{2}=\frac{36}{1}$
$\Rightarrow \frac{a_{1}+a_{2}}{a_{1}-a_{2}}=\frac{6}{1}$
$\Rightarrow \frac{a_{1}}{a_{2}}=\frac{7}{5}$
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