If resistivity of all four wire connected in parallel is different as given in figure and all other dimensions of wire are same then current

Q: If resistivity of all four wire connected in parallel is different as given in figure and all other dimensions of wire are same then current $i$ is (resistance of wire having resistivity $\rho $ is $R_0$ )

a $\mathrm{R}_{0}=\frac{\rho \mathrm{L}}{\mathrm{A}}=\frac{1}{\mathrm{R}}=\frac{1}{\mathrm{R}_{0}}+\frac{1}{2 \mathrm{R}_{0}}+\frac{1}{4 \mathrm{R}_{0}}+\frac{1}{6 \mathrm{R}_{0}}$ $=\frac{12+6+3+2}{12 R_{0}}$ $R=\frac{12 R_{0}}{23} \quad i=\frac{\varepsilon}{\left(\frac{2 R_{0}}{23}\right)}=\frac{23 \varepsilon}{12 R_{0}}$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

If resistivity of all four wire connected in parallel is different as given in figure and all other dimensions of wire are same then current $i$ is (resistance of wire having resistivity $\rho $ is $R_0$ )

A$\frac{{23\varepsilon }}{{12{R_0}}}$
B$\frac{{13\varepsilon }}{{12{R_0}}}$
C$\frac{{25\varepsilon }}{{16{R_0}}}$
D$\frac{{13\varepsilon }}{{6{R_0}}}$

Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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