MCQ
If $sin^{-1}\,\theta = sin^{-1}(sin\,5)$ then $\theta $ is
- A$sin\, (5 -\pi )$
- B$sin\, (2\pi -5)$
- ✓$sin\, (5 -2\pi )$
- DNone
$ \sin ^{-1} \theta =5-2 \pi $
$ \theta =\sin (5-2 \pi) $
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