MCQ
If $\sin 3 \alpha=4 \sin \alpha \sin (x+\alpha) \sin (x-\alpha)$, then $x=$
  • A
    $n \pi \pm \frac{\pi}{6}$
  • $n \pi \pm \frac{\pi}{3}$
  • C
    $n \pi \pm \frac{\pi}{4}$
  • D
    $n \pi \pm \frac{\pi}{2}$

Answer

Correct option: B.
$n \pi \pm \frac{\pi}{3}$
(B) $\sin 3 \alpha=4 \sin \alpha \sin (x+\alpha) \sin (x-\alpha)$
$\therefore \sin 3 \alpha=4 \sin \alpha\left(\sin ^2 x \cos ^2 \alpha-\cos ^2 x \sin ^2 \alpha\right)$
$\therefore 3 \sin \alpha-4 \sin ^3 \alpha=4 \sin \alpha\left(\sin ^2 x-\sin ^2 \alpha\right)$
$\therefore \quad \sin ^2 x=\left(\frac{3}{4}\right) \Rightarrow \sin ^2 x=\sin ^2 \frac{\pi}{3}$
$\therefore \quad x= n \pi \pm \frac{\pi}{3}$

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