If solid will break under pressure greater than $13\ atm$ and that solid has a specific gravity of $4$ , what is the maximum height of a cylinder made from the solid that can be built at the earth's surface ? (Note: $1\ atm$ = $10^5\ Pa$ .) ......... $m$
Medium
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$\mathrm{P}_{0} \mathrm{A}+\mathrm{hA} \rho \mathrm{g}=\mathrm{P}_{1} \mathrm{A}$
$\mathrm{h}=\frac{\mathrm{P}_{1}-\mathrm{P}_{0}}{\rho \mathrm{g}}$
$=\frac{12 \times 10^{5}}{4 \times 10^{3} \times 10}=30 \mathrm{m}$
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