MCQ
If $t =\sqrt{ x }+4$, then $\left(\frac{ dx }{ dt }\right)_{ t =4}$ is.
- A$4$
- ✓$0$
- C$8$
- D$16$
$\Rightarrow x =( t -4)^{2}= t ^{2}-8 t +16$
$\Rightarrow \frac{ dx }{ dt }=2 t -8$
$\left.\Rightarrow \frac{ dx }{ dt }\right|_{ t =4}=2 \times 4-8=0$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.


