MCQ
If $\tan \left( {\frac{\pi }{4} + \theta } \right) + \tan \left( {\frac{\pi }{4} - \theta } \right) = \lambda \sec 2\theta ,$ $\lambda$ =
- A$3$
- B$4$
- C$1$
- ✓$2$
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$(A)$ $a_x=1 ms ^{-2}$ implies that when the particle is at the origin, $a_y=1 ms ^{-2}$
$(B)$ $a_x=0$ implies $a_y=1 ms ^{-2}$ at all times
$(C)$ at $t=0$, the particle's velocity points in the $x$-direction
$(D)$ $a_x=0$ implies that at $t=1 s$, the angle between the particle's velocity and the $x$ axis is $45^{\circ}$