MCQ
If $\tan\theta = \frac{\text{a}}{\text{b}}$ then $\frac{\cos\theta+\sin\theta}{\cos\theta-\sin\theta}=$
  • A
    $\frac{\text{a}-\text{b}}{\text{a + b}}$
  • B
    $\frac{\text{b}-\text{b}}{\text{b+a}}$
  • $\frac{\text{b + a}}{\text{b}-\text{a}}$
  • D
    None of these

Answer

Correct option: C.
$\frac{\text{b + a}}{\text{b}-\text{a}}$
Given : $\tan\theta = \frac{\text{a}}{\text{b}}$
Dividing all terms of $\frac{\cos\theta+\sin\theta}{\cos\theta-\sin\theta}$ by $\cos\theta$
$=\frac{1+\tan\theta}{1-\tan\theta} =\frac{1+\frac{\text{a}}{\text{b}}}{1-\frac{\text{a}}{\text{b}}} = \frac{\text{b + a}}{\text{b}-\text{a}}$

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